2-16 할리데이 10판 솔루션 일반물리학
$$ x = 4.0- 6.0t^2 \cdots({2-16-1})$$ (a) $$ \Ans = t_{\dot x=0} =? $$ $$ \begin{aligned} \dot x &= \dxt{x} \\&= \dt(4.0- 6.0t^2) \\&= -12t=0 \end{aligned} $$ $$ t=0\ut{s} $$ (b) $$ \begin{aligned} \Ans &= x(0) =? \\ &= 4.0- 6.0(0)^2 \\ &= 4.0\ut{m} \end{aligned} $$ (c) $$ \Ans = t_{x=0,t0} =? $$ $$ (2-16-2), $$ $$ t = \sqrt{\frac{2}{3}} $$ (e) (f) +20t (그래프참조) (g) 증가시킴 (그래프참조)