솔루션피아

$$ \begin{aligned} A_n= A_0 \times (1-0.43)^n

$$\begin{aligned} & \Ans \\ =& 1.00\ut{cm} \cdot \sqrt[3]{1\ut{mol}} \\ =& 1.00\ut{cm}\cdot \frac{1\ut{m}}{100\ut{cm}} \cdot \sqrt[3]{1\ut{mol}\cdot \frac{6.02\times10^{23}\ut{EA}}{1\ut{mol}}} \\ =& \frac{1.00\cdot1\cdot\sqrt[3]{6.02\times10^{23}}}{100}\ut{m} \\ =& 100000\sqrt[3]{602}\ut{m} \\ \approx& 844368.773356757\ut{m} \\ \approx& 8.44\times 10^{5}\ut{m} = 844\ut{km} \end{aligned}$$

$$\begin{aligned} & \Ans \\ =& 3.8\ut{mm} \cdot \frac{1}{100} \\ =& 3.8\ut{mm} \cdot \frac{1\ut{m}}{1000\ut{mm}} \cdot \frac{1}{100} \\ =& \frac{38\cdot1\cdot1}{10\cdot1000\cdot100}\ut{m} \\ =& \frac{19}{500000}\ut{m} \\ =& 0.000038\ut{m} \\ =& 3.8\times 10^{-5}\ut{m} = 38\ut{\mu m} \end{aligned}$$

$$\begin{aligned} & \Ans \\=& 70.0\ut{mi/h} \cdot 1.00\ut{year} \\=& \frac{70\ut{mi}}{1\ut{h}} \cdot 1\ut{year}\cdot \frac{365.2422\ut{day}}{1\ut{year}}\cdot\frac{24\ut{h}}{1\ut{day}} \\=& \frac{70\cdot 1\cdot 365.2422\cdot 24}{1\cdot 1\cdot 1}\ut{mi} \\=& \frac{76700862}{125}\ut{mi} \\=& 613606.896\ut{mi} \\ \approx& 6.14\times10^{5}\ut{mi} \end{aligned}$$

(a) $$\begin{aligned} &5.00\ut{almude} \\ &= 5.00\ut{almude} \cdot \frac{2\ut{medio}}{1\ut{almude}} \\ &= 10\ut{medio} \\ &= 10.0\ut{medio} \end{aligned}$$ (b) $$\begin{aligned} &5.00\ut{almude} \\ &= 5.00\ut{almude} \cdot \frac{1\ut{cahiz}}{144\ut{almude}} \\ &= \frac{5}{144}\ut{cahiz} \\ &\approx 0.03472222222222222\ut{cahiz} \\ &\approx 3.47\times 10^{-2}\ut{cahiz} \end{aligned}$$ (c) $$ ..

$$\begin{aligned} & 2.0\ut{h} \\ =& 2.0\ut{h} \cdot \frac{3600\ut{s}}{1\ut{h}}\cdot \frac{24.0\ut{EA}}{1.0\ut{s}} \\ =& \frac{2.0 \cdot 3600 \cdot 24}{1\cdot 1}\ut{EA} \\ =& 172800\ut{EA} \\ \approx& 1.7\times 10^{5}\ut{EA} \end{aligned}$$

$$\begin{cases} 12 \ut{Point}=1 \ut{pica}\\ 6 \ut{pica}=1 \ut{inch}\\ 1 \ut{inch} = 2.540\ut{cm}\\ \end{cases}$$ (a) $$\begin{aligned} 0.70\ut{cm} =& 0.70\ut{cm} \times \(\frac{1 \ut{inch}}{2.540\ut{cm}}\)\times \(\frac{6 \ut{pica}}{1 \ut{inch}}\)\\ =&\frac{210}{127}\ut{pica}\\ \approx&1.65354330709\ut{pica}\\ \approx&1.65\ut{pica} \end{aligned}$$ (b) $$ \begin{aligned} 0.70\ut{cm} =& 0.70\ut..

$$\begin{aligned} & 1.0\ut{mi/h} \\ =& \frac{1\ut{mi}}{1\ut{h}} \cdot \frac{1609\ut{m}}{1\ut{mi}}\cdot \frac{1\ut{h}}{3600\ut{s}} \\ =& \frac{1\cdot1609\cdot1}{1\cdot1\cdot3600}\ut{m/s} \\ \approx& 0.4469444444444444 \ut{m/s} \\ \approx& 0.45 \ut{m/s} \end{aligned}$$

$$\begin{aligned} & 0.75\ut{gry^2} \\ =& 0.75\ut{gry^2} \(\frac{1\ut{line}}{10\ut{gry}}\)^2 \(\frac{1\ut{inch}}{12\ut{line}}\)^2 \(\frac{72\ut{Point}}{1\ut{inch}}\)^2 \\ =& \frac{0.75\cdot 1^2\cdot 1^2\cdot 72^2}{10^2\cdot12^2\cdot 1^2}\ut{Point^2} \\ =& \frac{27}{100}\ut{Point^2} \\ =& 0.27\ut{Point^2} \end{aligned}$$

$$\begin{aligned} & 14.0\ut{gal} \\ =& 14.0\ut{gal}\(\frac{231\ut{inch^3}}{1\ut{gal}}\)\(\frac{2.540\ut{cm}}{1\ut{inch}}\)^{3}\( \frac{1\ut{L}}{10^{3}\ut{cm^3}} \) \\ =& \frac{14.0\cdot231\cdot2.540^{3}\cdot1}{1\cdot1\cdot10^{3}}\ut{L} \\ =& \frac{3312235311}{62500000}\ut{L} \\ \approx& 52.995764976\ut{L} \\ \approx& 53.0\ut{L} \end{aligned}$$