$$ \begin{cases} m_{\max}&=22300\ut{kg}\\ V_0&=7682\ut{L}\\ \end{cases} $$ $$\ab{a,b}$$ $$k_A=1.77\ut{kg/L},$$ $$\ab{a}$$ $$ \begin{aligned} m_{A0}&=k_AV_0\\ &=1.77\ut{kg/L}\cdot7682\ut{L}\\ &=13597.14\ut{kg}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \Delta V&=\frac{\Delta m}{k_A}\\ &=\frac{m_{\max}-m_{A0}}{k_A}\\ &=\frac{870286}{177}\ut{L}\\ &\approx 4916.870056497175\ut{L}\\ &\approx 49..