11판/5. 힘과 운동 I

5-52 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 2. 22. 18:08
{m=0.400[kg]x(t[s])=(13.00+12.0t+3.00t22.00t3)i^[m]t=1.20[s] \begin{cases} m&=0.400\ut{kg}\\ x(t\ut{s})&=(-13.00+12.0t+3.00t^2-2.00t^3)\i\ut{m}\\ t&=1.20\ut{s} \end{cases} ΣF=ma=m ⁣d2x ⁣dt2=m ⁣d2 ⁣dt2(13+12t+3t22t3)i^=m(612t)i^=125(12t)i^ \begin{aligned} \Sigma F&=ma\\ &=m\dxtt{x}\\ &=m\cdot\dtt(-13+12t+3t^2-2t^3)\i\\ &=m(6-12t)\i\\ &=\frac{12}{5}(1-2t)\i \end{aligned} F(1.2)=8425i^[N]=3.36i^[N] \begin{aligned} F(1.2)&=-\frac{84}{25}\i\ut{N}\\ &=-3.36\i\ut{N}\\ \end{aligned}