5-51 할리데이 11판 솔루션 일반물리학

$$\begin{cases} m_1&=4.00\ut{kg}\\ m_2&=3.00\ut{kg}\\ \theta_1&=25.0\degree\\ \theta_2&=65.0\degree\\ \end{cases}$$ $$\Sigma \vec F = m\vec a,$$ $$\begin{cases} \Sigma F_1 &= m_1 a\\ \Sigma F_2 &= m_2 a\\ \end{cases}$$ $$\begin{cases} T-m_1g\sin\theta_1 &= m_1 a\\ m_2g\sin\theta_2-T &= m_2 a\\ \end{cases}$$ $$\begin{aligned} T&= m_1 g(\sin\theta _1+ \sin \theta _2)\\ &\approx 52.12925054496957\ut{N}\\ &\approx 52.1\ut{N}\\ \end{aligned}$$