11판/5. 힘과 운동 I

5-55 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 2. 23. 18:34
{m=5.0×104[kg]g=9.80665[m/s2] \begin{cases} m&=5.0\times10^4\ut{kg}\\ g&=9.80665\ut{m/s^2} \end{cases} (a)\ab{a} ΣF=0Δv=0,\Sigma \vec F = 0 \Harr \Delta \vec v=0, ΣF=Fmg=0F=mg=9806652[N]=490332.5[N]4.9×105[N] \begin{aligned} \Sigma F &= F-mg= 0\\ F&=mg\\ &=\frac{980665}{2}\ut{N}\\ &=490332.5\ut{N}\\ &\approx 4.9\times10^5\ut{N} \end{aligned} (b)\ab{b} ΣF=ma,\Sigma \vec F = m\vec a, Fmg=maF=m(a+g)=29806652[N]=1490332.5[N]1.5×106[N]1.5[MN] \begin{aligned} F-mg &= m a\\ F&=m(a+g)\\ &=\frac{2980665}{2}\ut{N}\\ &=1490332.5\ut{N}\\ &\approx 1.5\times10^6\ut{N}\\ &\approx 1.5\ut{MN}\\ \end{aligned}