1-15 할리데이 10판 솔루션 일반물리학

$$ \begin{aligned} & 1\ut{fortnight} \\ =& 1\ut{fortnight} \cdot \frac{14\ut{days}}{1\ut{fortnight}}\cdot \frac{24\ut{h}}{1\ut{days}}\cdot\frac{3600\ut{s}}{1\ut{h}}\cdot\frac{10^6[\mu s]}{1\ut{s}} \\ =& 14 \cdot24\cdot3600\cdot10^6[\mu s] \\ =& 1209600000000[\mu s] \\ \approx& 1\times10^{12}[\mu s] \end{aligned} $$