1-16 할리데이 10판 솔루션 일반물리학

$$T =1.55780644887275±3\ut{ms}$$ $$\begin{cases} 1.55780644887278\ut{ms} &= T_{Max} &=T_M \\ 1.55780644887272\ut{ms} &= T_{min} &= T_m \end{cases}$$
(a) $x\ut{cycle/8days}=?$
(i) $T_M$ $$\begin{aligned} & \frac{1\ut{cycle}}{1.55780644887278\ut{ms}} \cdot 8.00\ut{days} \\ &= \frac{1\ut{cycle}}{1.55780644887278\ut{ms}} \cdot 8.00\ut{days} \cdot \frac{24\ut{h}}{1\ut{days}}\cdot \frac{3600\ut{s}}{1\ut{h}}\cdot \frac{1000\ut{ms}}{1\ut{s}} \\ &= \frac{34560000000000000000000}{77890322443639}\ut{cycle} \\ &\approx 4.437008207920493\times 10^8\ut{cycle} \\ &\approx 4.44\times 10^8\ut{cycle} \end{aligned}$$
(ii) $T_m$ $$\begin{aligned} & \frac{1\ut{cycle}}{1.55780644887272\ut{ms}} \cdot 8.00\ut{days} \\ &= \frac{1\ut{cycle}}{1.55780644887272\ut{ms}} \cdot 8.00\ut{days} \cdot \frac{24\ut{h}}{1\ut{days}}\cdot \frac{3600\ut{s}}{1\ut{h}}\cdot \frac{1000\ut{ms}}{1\ut{s}} \\ &= \frac{8640000000000000000000}{19472580610909}\ut{cycle} \\ &\approx 4.437008207920663\times 10^8\ut{cycle} \\ &\approx 4.44\times 10^8\ut{cycle} \\ \\ \therefore& 4.44\times 10^8\ut{cycle} \end{aligned}$$
(b)$x\ut{s/1000000cycle} =?$ (i) $T_M$ $$\begin{aligned} &\frac{1.55780644887278\ut{ms}}{1\ut{cycle}} \cdot 1000000\ut{cycle}\cdot \frac{1\ut{s}}{1000\ut{ms}} \\&= 1557.80644887278\ut{s} \end{aligned}$$
(ii) $T_m$ $$\begin{aligned} &\frac{1.55780644887272\ut{ms}}{1\ut{cycle}} \cdot 1000000\ut{cycle}\cdot \frac{1\ut{s}}{1000\ut{ms}} \\&= 1557.80644887272\ut{s} \end{aligned}$$ $$\begin{aligned} \\ \therefore& 1557.80644887275\pm 3\times 10^{-11}\ut{s} \end{aligned}$$
(c) $$\begin{aligned} 3\times 10^{-11}\ut{s} = 30\ut{ps} \end{aligned}$$