12-14 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} F_h&=13.4\ut{N}\\ F_v&=162.4\ut{N}\\ \end{cases} $$ $$ \begin{aligned} \Sigma \tau&=-{d\over3}F_t\sin45\degree+d F_v \sin10\degree+dF_h\sin80\degree\\ &=0 \end{aligned} $$ $$ \begin{aligned} F_t &=3\sqrt2\br{F_h\cos10\degree+F_v\sin10\degree}\\ &={3\sqrt2\over5}\br{67\cos10\degree+812\sin10\degree}\\ &\approx 175.63212110909666\ut{N}\\ &\approx 176\ut{N}\\ \end{aligned} $$