10-59 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} 2R&=0.52\ut{m}\\ t&=8.9\ut{s}\\ v_i&=12\ut{m/s}\\ v_f&=33\ut{m/s}\\ \end{cases} $$ $$v=r\omega$$ $$\omega=\omega_0+\alpha t,$$ $$ \begin{aligned} \bar \alpha &=\frac{\omega_f-\omega_i}{t}\\ &=\frac{Rv_f-Rv_i}{t}\\ &=\frac{v_f-v_i}{2t}(2R)\\ &=\frac{546}{89}\ut{rad/s^2}\\ &\approx 6.134831460674158\ut{rad/s^2}\\ &\approx 6.1\ut{rad/s^2}\\ \end{aligned} $$