11판/9. 질량중심과 선운동량

9-14 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 4. 16. 18:41
{m1=16.7×1027[kg]m2=8.35×1027[kg]m3=11.7×1027[kg]v1=+6.00×106i^[m/s]v2=8.00×106j^[m/s] \begin{cases} m_1&=16.7\times10^{-27}\ut{kg}\\ m_2&=8.35\times10^{-27}\ut{kg}\\ m_3&=11.7\times10^{-27}\ut{kg}\\ \vec v_1&=+6.00\times10^6\i\ut{m/s}\\ \vec v_2&=-8.00\times10^6\j\ut{m/s}\\ \end{cases} (a)\ab{a} ΔΣP=0,\Delta \Sigma \vec P=0, Pi=ΣPf \vec P_i=\Sigma \vec P_f 0=m1v1+m2v2+m3v3 0=m_1\vec v_1+m_2\vec v_2+m_3\vec v_3 v3=m1v1m2v2m3=m1m3v1m2m3v2={16.711.76i^8.3511.7(8)j^}×106[m/s]=(33439i^+668117j^)×106[m/s](8.564102564102564i^      +5.7094017094017095j^)×106[m/s](8.56i^+5.71j^)×106[m/s]8.56i^+5.71j^[Mm/s] \begin{aligned} \vec v_3&=\frac{-m_1\vec v_1-m_2\vec v_2}{m_3}\\ &=-\frac{m_1}{m_3}\vec v_1-\frac{m_2}{m_3}\vec v_2\\ &=\bra{-\frac{16.7}{11.7}\cdot6\i-\frac{8.35}{11.7}\cdot(-8)\j} \times10^6\ut{m/s}\\ &=\(-\frac{334}{39}\i+\frac{668}{117}\j\) \times10^6\ut{m/s}\\ &\approx (-8.564102564102564\i\\ &~~~~~~+5.7094017094017095\j)\times10^6\ut{m/s}\\ &\approx (-8.56\i+5.71\j)\times10^6\ut{m/s}\\ &\approx -8.56\i+5.71\j\ut{Mm/s}\\ \end{aligned} (b)\ab{b} ΔKE=KEfKEi=KEf=12m1v12+12m2v22+12m3v32=9001314625×1013[J]6.154735042735043×1013[J]6.15×1013[J]615×1015[J]615[fJ] \begin{aligned} \Delta \KE&=\KE_f-\KE_i\\ &=\KE_f\\ &=\frac{1}{2}m_1{v_1}^2+\frac{1}{2}m_2{v_2}^2+\frac{1}{2}m_3{v_3}^2\\ &=\frac{90013}{14625}\times10^{-13}\ut{J}\\ &\approx 6.154735042735043\times10^{-13}\ut{J}\\ &\approx 6.15\times10^{-13}\ut{J}\\ &\approx 615\times10^{-15}\ut{J}\\ &\approx 615\ut{fJ}\\ \end{aligned}