11판/9. 질량중심과 선운동량

9-13 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 4. 15. 21:19
put {A:3d x 3d BoxB:2d x 2d BoxC:A-B Box \put\begin{cases} A:\text{3d x 3d Box}\\ B:\text{2d x 2d Box}\\ C:\text{A-B Box} \end{cases} {6d=6.0[m] \begin{cases} 6d&=6.0\ut{m}\\ \end{cases} (a)\ab{a} {xcomA=0xcomB=2d \begin{cases} x_{\com A} &=0\\ x_{\com B}&=2d\\ \end{cases} rcom=ΣmrM=ΣVrVs,\vec r_{\com} = \frac{\Sigma m\vec r}{M}= \frac{\Sigma V\vec r}{V_s}, xcomA=ΣVrVA=VBxcomB+VCxcomCVA \begin{aligned} x_{\com A}&= \frac{\Sigma V\vec r}{V_A}\\ &=\frac{V_Bx_{\com B}+V_Cx_{\com C}}{V_A}\\ \end{aligned} xcomC=VAxcomAVBxcomBVC=h(6d)2xcomAh(2d)2xcomBh(6d)2h(2d)2=62022(2d)6222=d4=2.0[m] \begin{aligned} x_{\com C}&=\frac{V_Ax_{\com A}-V_Bx_{\com B}}{V_C}\\ &=\frac{h(6d)^2x_{\com A}-h(2d)^2x_{\com B}}{h(6d)^2-h(2d)^2}\\ &=\frac{6^2\cdot0-2^2\cdot(2d)}{6^2-2^2}\\ &=-\frac{d}{4}\\ &=-2.0\ut{m}\\ \end{aligned} (b)\ab{b} Symmetrical about y,\text{Symmetrical about }y, ycomC=0y_{\com C}=0