솔루션피아

$$ \begin{cases} \theta&=36.9\degree\\\phi&=53.1\degree\\L&=4.35\ut{m}\\\end{cases} $$$$L=x+y,$$$$ \begin{cases} \Sigma F_{x}&=0\\\Sigma F_{y}&=0\\\Sigma \tau&=0\\\end{cases} $$$$ \begin{cases} 0&=-T_1\sin\theta+T_2\sin\phi\\0&=T_1\cos\theta+T_2\cos\phi-mg\\0&=-xT_1\cos\theta+yT_2\cos\phi\\\end{cases} $$$$ \begin{aligned}x&={\cos\phi\sin\theta\over\sin\br{\theta+\phi}}L\\&=L \sin ^236.9\degree\\..

$$ \begin{cases} mg&=60\ut{N}\\L&=3.2\ut{m}\\F&=50\ut{N}\\\theta&=25\degree\\h&=2.0\ut{m}\\\end{cases} $$$$ \begin{cases} \Sigma F_{x}&=0\\\Sigma F_{y}&=0\\\Sigma \tau&=0\\\end{cases} $$$$ \begin{cases} 0&=F+N_x-T\cos\theta\\0&=N_y-mg-T\sin\theta\\0&=hT\cos\theta-LF\\\end{cases} $$$$ \begin{cases} T&={F L\over h\cos\theta}\\N_x&={F(L-h)\over h}\\N_y&={FL\over h}\tan\theta+mg\\\end{cases} $$$$\ab..

$$ \begin{cases} 2R&=4.8\ut{cm}\\L&=5.3\ut{cm}\\m&=1500\ut{kg}\\G&=3.0\times10^{10}\ut{N/m^2}\\g&=9.80665\ut{m/s^2}\\\end{cases} $$$$\ab{a}$$$$ \begin{aligned}F&=mg\\&=14709.975\ut{N}\\&\approx 1.5\times10^4\ut{N}\\&\approx 15\ut{kN}\\\end{aligned} $$$$\ab{b}$$$${F\over A}=G{\Delta x\over L},$$$$ \begin{aligned}\Delta x&={FL\over AG}\\&={Lmg\over \pi R^2 G}\\&=\frac{53 g}{11520000 \pi }\ut{m}\\&..

$$ \begin{cases} \theta_1&=51.0\degree\\\theta_2&=66.0\degree\\m&=704\ut{kg}\\g&=9.80665\ut{m/s^2}\end{cases} $$$$\ab{a}$$$$ \begin{aligned}T_A&=mg\\&=6.9038816\times10^3\ut{N}\\&\approx 6.90\times10^3\ut{N}\\&\approx 6.90\ut{kN}\\\end{aligned} $$$$\ab{b,c}$$$$ \begin{cases} \theta&=\theta_1+\theta_2-90\degree&=27.0\degree\\\phi&=90\degree-\theta_2&=24.0\degree\\\end{cases} $$$$ \begin{aligned}0..