10판/2. 직선운동

2-25 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 7. 24. 21:16

{t=2.5[s]S=8.0[m]2.0[m]=6.0[m]v0=2.8[m/s]a=Constant \begin{cases} t&=2.5\ut{s} \\S &= 8.0\ut{m}-2.0\ut{m} = 6.0\ut{m} \\ v_0 &= 2.8\ut{m/s} \\ a &= \Cons \end{cases} a=?a=? S=v0t+12at2 S = v_0t+\frac{1}{2}at^2 Ans=a=2(Sv0t)t2=2{6.0[m](2.8[m/s])(2.5[s])}(2.5[s])2=825[m/s2]=0.32[m/s2] \begin{aligned} \\ \Ans &= a = \frac{2(S-v_0t)}{t^2} \\ &= \frac{2\{6.0\ut{m}-(2.8\ut{m/s})(2.5\ut{s})\}}{(2.5\ut{s})^2} \\ &= -\frac{8}{25}\ut{m/s^2} \\ &= -0.32\ut{m/s^2} \end{aligned}