10판/2. 직선운동

2-27 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 7. 24. 22:14

{v0=0a=Constantt=5.00[ms]=0.005[s]S=2.00[cm]=0.02[m] \begin{cases} v_0 &= 0 \\ a &= \Cons \\ t &= 5.00\ut{ms} = 0.005\ut{s} \\ S &= 2.00\ut{cm} = 0.02\ut{m} \end{cases} a=? a =? S=v0t+12at2=12at2(v0=0)\begin{aligned} S &= v_0t+\frac{1}{2}at^2 \\ &= \frac{1}{2}at^2 (\because v_0=0) \end{aligned} Ans=a=2St2=2(0.02[m])(0.005[s])2=8.00[m/s] \begin{aligned} \Ans &= a = \frac{2S}{t^2} \\ &=\frac{2(0.02\ut{m})}{(0.005\ut{s})^2} \\ &= 8.00\ut{m/s} \end{aligned}