10판/2. 직선운동

2-23 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 7. 24. 20:17

{v0=0a=ConstanttA=15[s]tB=5.00[s] \begin{cases} v_0 &= 0 \\ a &= \Cons \\ t_A &= \frac{1}{5}\ut{s} \\ t_B &= 5.00\ut{s} \end{cases} Ans=SA:SB=? \Ans = S_A : S_B =? S=v0t+12at2=12at2(v0=0)\begin{aligned} \\ S &= v_0t+\frac{1}{2}at^2 \\ &= \frac{1}{2}at^2 (\because v_0=0) \end{aligned} Ans=SA:SB=12atA2:12atB2=tA2:tB2=(15[s])2:(5.00[s])2=1:625 \begin{aligned} \Ans &= S_A : S_B \\ &= \frac{1}{2}at_A^2 : \frac{1}{2}at_B^2 \\ &= t_A^2 : t_B^2 \\ &= \left(\frac{1}{5}\ut{s}\right)^2 : (5.00\ut{s})^2 \\ &= 1:625 \end{aligned}