11-38 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} L_i&=-600\ut{kg\cdot m^2/s}\\ \tau&=+60\ut{N\cdot m}\\ \end{cases} $$ $$\vec L=I\omega,$$ $$\omega_f=0\Rarr L_f=0$$ $$\vec \tau_\net=\dyt{\vec L}={\Delta L\over \Delta t},$$ $$ \begin{aligned} \Delta t&={\Delta L\over \tau}\\ &={L_f-L_i\over \tau}\\ &={-L_i\over \tau}\\ &=10\ut{s} \end{aligned} $$