11-9 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} m&=10\ut{kg}\\ R&=0.30\ut{m}\\ \vec F_1&=10\i\ut{N}\\ \vec a&=0.90\i\ut{m/s^2} \end{cases} $$ $$ \begin{cases} \Sigma \vec F&=m\vec a\\ \Sigma \tau&=I \alpha\\ a&=R\alpha \end{cases} $$ $$ \begin{cases} \vec F_1-f&=m\vec a\\ -Rf&=I (-\alpha)\\ a&=R\alpha \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \vec f&=\vec F_1-m\vec a\\ &=1.0\i\ut{N}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} I&=\(\frac{ F_1}{a}- m\)R^2\\ &=\frac{1}{10}\ut{kg\cdot m^2}\\ &=0.10\ut{kg\cdot m^2}\\ \end{aligned} $$