11판/9. 질량중심과 선운동량

9-22 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 4. 18. 21:19
put {0:Start1:After Crash2:Highest Point \put \begin{cases} 0:\text{Start}\\ 1:\text{After Crash}\\ 2:\text{Highest Point} \end{cases} {mA=3.0[kg]vA0=28[m/s]mB=2.0[kg]vB0=12[m/s]M=mA+mB=5[kg]g=9.80665[m/s2] \begin{cases} m_A&=3.0\ut{kg}\\ v_{A0}&=28\ut{m/s}\\ m_B&=2.0\ut{kg}\\ v_{B0}&=-12\ut{m/s}\\ M&=m_A+m_B=5\ut{kg}\\ g&=9.80665\ut{m/s^2} \end{cases} put {KE:Kinetic EnergyGE:Gravitational Potential Energy \put \begin{cases} \KE : \text{Kinetic Energy}\\ \GE : \text{Gravitational Potential Energy}\\ \end{cases} ΔΣP=0,\Delta \Sigma \vec P=0, Mv1=mAvA0+mBvB0v1=mAvA0+mBvB0M=12[m/s] \begin{aligned} Mv_1&=m_Av_{A0}+m_Bv_{B0}\\ v_1&=\frac{m_Av_{A0}+m_Bv_{B0}}{M}\\ &=12\ut{m/s} \end{aligned} ΣΔE=0,\Sigma \Delta E=0, ΔGE=ΔKEmgΔh=12mΔ(v2) \begin{aligned} \Delta \GE&=-\Delta \KE\\ mg\Delta h&=-\frac{1}{2}m\Delta(v^2)\\ \end{aligned} h2=v12v222g=v122g=72g7.341956733441084[m]7.3[m] \begin{aligned} h_2&=\frac{{v_1}^2-{v_2}^2}{2g}\\ &=\frac{{v_1}^2}{2g}\\ &=\frac{72}{g}\\ &\approx 7.341956733441084\ut{m}\\ &\approx 7.3\ut{m}\\ \end{aligned}