1-31 할리데이 10판 솔루션 일반물리학

$$ \begin{aligned} \rho &= \frac{m}{V} \\ &= \frac{0.0200\ut{g}}{50.0\ut{mm^3}} \cdot \frac{1\ut{kg}}{1000\ut{g}}\cdot \(\frac{10\ut{mm}}{1\ut{cm}}\)^3 \\ &= \frac{1}{2500}\ut{kg/cm^3} = 0.0004\ut{kg/cm^3} \end{aligned} $$ $$ \begin{aligned} \\ \Ans &= \dot m= \dxt{m} \\ &= \dxt{\rho V} = \dxt{\rho Sh} \\ &= \rho S\dxt{h} \\ &= \frac{1}{2500}\ut{kg/cm^3}\cdot 14.0\ut{cm} \cdot 17.0\ut{cm} \cdot 0.250\ut{cm/s} \cdot \frac{60\ut{s}}{1\ut{min}} \\ &= \frac{357}{250}\ut{kg/min} \\ &= 1.428\ut{kg/min} \\ &\approx 1.43\ut{kg/min} \end{aligned} $$