1-28 할리데이 10판 솔루션 일반물리학

$$ \begin{cases} c &= 299792458\ut{m/s} \\ 1\ut{MeV} &= 1.60218 \times 10^{-13}\ut{J} \\ 1\ut{u} &= 1.66054 \times 10^{-27}\ut{kg} \end{cases} $$ $$ \begin{aligned} \\ \Ans &= E = ? \\&= E = mc^2 \\&= 1\ut{u} \cdot (299792458\ut{m/s})^2 \\&= 1\ut{u} \cdot (299792458\ut{m/s})^2 \cdot \frac{1.66054 \times 10^{-27}\ut{kg}}{1\ut{u}}\cdot \frac{1\ut{MeV}}{1.60218 \times 10^{-13}\ut{J}} \\&= \frac{1865523655624543954907}{2002725000000000000}\ut{MeV} \\&\approx 931.4926690506904\ut{MeV} \\&\approx 931.5\ut{MeV} \end{aligned} $$