1-29 할리데이 10판 솔루션 일반물리학

$$ \begin{aligned} \\ \Ans &= 28.9\ut{picul} = ? \\&= 28.9\ut{picul} \cdot \frac{100\ut{gin}}{1\ut{picul}} \cdot \frac{16\ut{tahil}}{1\ut{gin}}\cdot \frac{10\ut{chee}}{1\ut{tahil}}\cdot \frac{10\ut{hoon}}{1\ut{chee}}\cdot \frac{0.3779\ut{g}}{1\ut{hoon}}\cdot \frac{1\ut{kg}}{1000\ut{g}} \\&= \frac{1092131}{625}\ut{kg} \\&= 1747.4096\ut{kg} \\&\approx 1.75 \times 10^3\ut{kg} = 1750\ut{kg} \end{aligned} $$