6-52 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} m&=85.0\ut{kg}\\ g&=9.80665\ut{m/s^2} \end{cases} $$ $$\Sigma F_{R} = \frac{mv^2}{R},$$ $$ \begin{cases} \Sigma F_{R1}&=mg = \cfrac{mv^2}{R}\\ \Sigma F_{R2}&=F_N-mg = \cfrac{mv^2}{R}\\ \end{cases} $$ $$ \begin{aligned} F_N-mg&=mg\\ F_N&=2mg\\ &=170g\\ &=1667.1305\ut{N}\\ &=1.67\ut{kN}\\ \end{aligned} $$