6-53 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \mu&=0.70\\ R&=34.0\ut{m} \end{cases} $$ $$\Sigma F_R = \frac{mv^2}{R},$$ $$\mu mg= \frac{mv^2}{R}$$ $$ \begin{aligned} v&=\sqrt{\mu gR}\\ &\approx 15.27737772001465\ut{m/s}\\ &\approx 15.3\ut{m/s}\\ \end{aligned} $$