5-28 할리데이 11판 솔루션 일반물리학

$$\begin{cases} m_1&=2.00\ut{kg}\\ m_2&=2.70\ut{kg}\\ a&=4.50\ut{m/s^2}\\ F&=7.00\ut{N}\\ g&=9.80665\ut{m/s^2}\\ \end{cases}$$ $$\Sigma \vec F = m\vec a,$$ $$\begin{cases} \Sigma F_1 &= m_1 a\\ \Sigma F_2 &= m_2 a\\ \end{cases}$$ $$\begin{cases} T+m_1g\sin\beta &= m_1 a\\ m_2g-T-F&= m_2 a\\ \end{cases}$$ $$\ab{a}$$ $$\begin{aligned} T&=\frac{1}{20} (54 g-383)\\ &\approx 7.327954999999998\ut{N}\\ &\approx 7.33\ut{N}\\ \end{aligned}$$ $$\ab{b}$$ $$\begin{aligned} \beta&= \sin ^{-1}\frac{563-54 g}{40 g}\\ &\approx 0.08535417096853244\ut{rad}\\ &\approx 0.0854\ut{rad}\\ \end{aligned}$$