5-29 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} m_A&=60\ut{kg}\\ m_B&=5.0\ut{kg}\\ a&=2.8\ut{m/s^2}\\ \end{cases} $$ $$\Sigma \vec F = m\vec a,$$ $$ \begin{cases} \Sigma F_A &= m_A a\\ \Sigma F_B &= m_B a\\ \end{cases} $$ $$ \begin{cases} T-m_Ag &= -m_A a\\ F-T-m_Bg &= -m_B a\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} F&=13 (5 g-14)\\ &=455.43225\ut{N}\\ &\approx 4.6\times10^2\ut{N}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} T&=12 (5 g-14)\\ &=420.3989999999999\ut{N}\\ &\approx 4.2\times10^2\ut{N}\\ \end{aligned} $$