5-27 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \theta &= 30.0\degree\\ F&=510\ut{N}\\ f&=90.0\ut{N}\\ g&=9.80665\ut{m/s^2} \end{cases} $$ $$ \begin{aligned} a&=\frac{\Sigma F}{m}\\ &=\frac{F\cos30\degree-f}{m}\\ &=\frac{255\sqrt3-90}{m}\\ \end{aligned} $$ $$\ab{a}$$ $$ \begin{aligned} m_1&=282\ut{kg}\\ a_1&=\frac{255\sqrt3-90}{282}\\ &\approx 1.247067219610155\ut{m/s^2}\\ &\approx 1.25\ut{m/s^2} \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} m_2g&=282\ut{N}\\ a_2&=\frac{255\sqrt3-90}{282}g\\ &\approx 12.22955174918992\ut{m/s^2}\\ &\approx 12.2\ut{m/s^2} \end{aligned} $$