2-31 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \Delta t&=6.50\ut{ms}=6.50\times10^{-3}\ut{s}\\ a&=-3400g\\ g&=9.80665\ut{m/s^2} \end{cases} $$ $$ \begin{aligned} v&=v_0+at,\\ 0&=v_0+(-3400g)(6.50\times10^{-3}\ut{s}),\\ \end{aligned} $$ $$ \begin{aligned} v_0&=\frac{221}{10}g\\ &=\frac{43345393}{200000}\ut{m/s}\\ &=216.726965\ut{m/s}\\ &\approx 217\ut{m/s}\\ \end{aligned} $$