2-33 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} h&=35.0\ut{m}\\ v&=1100\ut{km/h}=\dfrac{2750}{9}\ut{m/s}\\ \theta&=4.30\degree\\ \end{cases} $$ $$ \begin{aligned} \Delta x &= \frac{h}{\tan\theta}\\ vt&=\frac{h}{\tan\theta}\\ t&=\frac{h}{v\tan\theta}\\ &=\frac{35}{\(\dfrac{2750}{9}\)\tan4.3\degree}\ut{s}\\ &=\frac{63}{550}\cot4.3\degree\ut{s}\\ &\approx 1.523405760812364\ut{s}\\ &\approx 1.52\ut{s} \end{aligned} $$