11판/2. 직선운동

2-17 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 1. 11. 18:49
12-23 할리데이 11판 솔루션 일반물리학 {A : CarB : Truck \begin{cases} \text{A : Car}\\ \text{B : Truck} \end{cases} {aA=1.80[m/s2]vA0=0vB=7.30[m/s] \begin{cases} a_A&=1.80\ut{m/s^2}\\ v_{A0}&=0\\ v_B&=7.30\ut{m/s} \end{cases} (a)\ab{a} S=v0t+12at2,S=v_0t+\frac{1}{2}at^2, S=v0t+12at2vBt=(0)t+12(aA)t2(7.30[m/s])=12(1.80[m/s2])t \begin{aligned} S&=v_0t+\frac{1}{2}at^2\\ v_Bt&=(0)t+\frac{1}{2}(a_A)t^2\\ \(7.30\ut{m/s}\)&=\frac{1}{2}\(1.80\ut{m/s^2}\)t\\ \end{aligned} t=739[s] t=\frac{73}{9}\ut{s} S=vt=(7.30[m/s])(739[s])=532990[m]59.21111111111111[m]59.2[m] \begin{aligned} S &= vt\\ &=\(7.30\ut{m/s}\)\cdot\(\frac{73}{9}\ut{s}\)\\ &=\frac{5329}{90}\ut{m}\\ &\approx59.21111111111111\ut{m}\\ &\approx59.2\ut{m}\\ \end{aligned} (b)\ab{b} v=v0+at,v=v_0+at, v=(0)+(1.80[m/s2])(739[s])=735[m/s]=14.6[m/s] \begin{aligned} v&=(0)+\(1.80\ut{m/s^2}\)\(\frac{73}{9}\ut{s}\)\\ &=\frac{73}{5}\ut{m/s}\\ &=14.6\ut{m/s}\\ \end{aligned}