10판/4. 2차원운동과 3차원운동

4-13 할리데이 10판 솔루션 일반물리학

짱세디럭스 2020. 6. 29. 16:39
r=i^+3t4j^+tk^[m]\vec r=\i+3t^4\j+ t\k\ut{m}
(a) v= ⁣dr ⁣dt= ⁣d ⁣dt(i^+3t4j^+tk^)=12t3j^+k^[m/s]\begin{aligned} \vec v &= \dxt{\vec r}\\ &=\dt(\i+3t^4\j+ t\k)\\ &=12t^3\j+\k\ut{m/s}\\ \end{aligned}
(b) a= ⁣dv ⁣dt= ⁣d ⁣dt(12t3j^+k^)=36t2j^[m/s2]\begin{aligned} \vec a &= \dxt{\vec v}\\ &=\dt(12t^3\j+\k)\\ &=36t^2\j\ut{m/s^2}\\ \end{aligned}