솔루션피아

$$ \begin{cases} \theta&=36.9\degree\\\phi&=53.1\degree\\L&=4.35\ut{m}\\\end{cases} $$$$L=x+y,$$$$ \begin{cases} \Sigma F_{x}&=0\\\Sigma F_{y}&=0\\\Sigma \tau&=0\\\end{cases} $$$$ \begin{cases} 0&=-T_1\sin\theta+T_2\sin\phi\\0&=T_1\cos\theta+T_2\cos\phi-mg\\0&=-xT_1\cos\theta+yT_2\cos\phi\\\end{cases} $$$$ \begin{aligned}x&={\cos\phi\sin\theta\over\sin\br{\theta+\phi}}L\\&=L \sin ^236.9\degree\\..

$$ \begin{cases} mg&=60\ut{N}\\ L&=3.2\ut{m}\\ F&=50\ut{N}\\ \theta&=25\degree\\ h&=2.0\ut{m}\\ \end{cases} $$ $$ \begin{cases} \Sigma F_{x}&=0\\ \Sigma F_{y}&=0\\ \Sigma \tau&=0\\ \end{cases} $$ $$ \begin{cases} 0&=F+N_x-T\cos\theta\\ 0&=N_y-mg-T\sin\theta\\ 0&=hT\cos\theta-LF\\ \end{cases} $$ $$ \begin{cases} T&={F L\over h\cos\theta}\\ N_x&={F(L-h)\over h}\\ N_y&={FL\over h}\tan\theta+mg\\ \e..

$$ \begin{cases} 2R&=4.8\ut{cm}\\ L&=5.3\ut{cm}\\ m&=1500\ut{kg}\\ G&=3.0\times10^{10}\ut{N/m^2}\\ g&=9.80665\ut{m/s^2}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} {F\over A}&={mg\over \pi R^2}\\ &=\frac{7812500 g}{3 \pi }\\&\approx 8.129045951417372\times10^6\ut{N/m^2}\\ &\approx 8.1\ut{MN/m^2}\\ \end{aligned} $$ $$\ab{b}$$ $${F\over A}=G{\Delta x\over L},$$ $$ \begin{aligned} \Delta x&={FL\..

$$ \begin{cases} \theta_1&=51.0\degree\\\theta_2&=66.0\degree\\m&=704\ut{kg}\\g&=9.80665\ut{m/s^2}\end{cases} $$$$\ab{a}$$$$ \begin{aligned}T_A&=mg\\&=6.9038816\times10^3\ut{N}\\&\approx 6.90\times10^3\ut{N}\\&\approx 6.90\ut{kN}\\\end{aligned} $$$$\ab{b,c}$$$$ \begin{cases} \theta&=\theta_1+\theta_2-90\degree&=27.0\degree\\\phi&=90\degree-\theta_2&=24.0\degree\\\end{cases} $$$$ \begin{aligned}0..

(풀이자 주:축에서 가해지는 힘이 없다고 가정했습니다. 그러지 않을 경우 각각의 힘을 특정할 수 없습니다.)$$ \begin{cases} r_A&=7.0\ut{cm}\\ r_B&=4.0\ut{cm}\\ R&=4.0\ut{cm}\\ F&=220\ut{N}\\ \end{cases} $$ $$ \begin{cases} 0&=F-N_A+N_B\\ 0&=RF-r_AN_A-r_BN_B \end{cases} $$ $$ \begin{cases} N_A&=\cfrac{R+r_B}{2r_B}F\\ N_B&=\cfrac{R-r_B}{2r_B}F\\ \end{cases} $$ $$\ab{a,b}$$ $$ \begin{cases} N_A&=220\ut{N}\\ N_B&=0\\ \end{cases} $$

$$ \put \begin{cases} A : \text{Top Ball}\\B : \text{Bottom Ball}\\L : \text{Left Wall}\\R : \text{Right Wall}\\G : \text{Ground}\\\end{cases} $$$$ \begin{cases} \Sigma F_{Ax}&=0\\\Sigma F_{Ay}&=0\\\Sigma F_{Bx}&=0\\\Sigma F_{By}&=0\\\end{cases} $$$$ \begin{cases} 0&=N_{ABx}-N_R\\0&=N_{ABy}-mg\\0&=N_L-N_{ABx}\\0&=N_G-N_{ABy}-mg\\\end{cases} $$$$\theta=45\degree\Rarr N_{ABx}=N_{ABy}$$$$\ab{a,b,c,..

$$ \begin{cases} L&=2.00\ut{m}\\m&=78.0\ut{kg}\\d_h&=3.00\ut{m}\\d_v&=4.00\ut{m}\\g&=9.80665\ut{m/s^2}\end{cases} $$$$x_1=d_h-{L\over2},$$$$\theta=\tan^{-1}{d_h\over d_v}$$$$ \begin{cases} \Sigma F_{x}&=0\\\Sigma F_{y}&=0\\\Sigma \tau&=0\\\end{cases} $$$$ \begin{cases} 0&=N_x-T\sin\theta\\0&=N_y+T\cos\theta-mg\\0&=-x_1 mg+Td_h\cos\theta\\\end{cases} $$$$\ab{a}$$$$ \begin{aligned}T&= {x_1 mg\over..

$$ \begin{cases} \Sigma F_{y}&=0\\\Sigma \tau&=0\\\end{cases} $$$$ \begin{cases} 0&=3F-mg\\0&=x\cdot 2F+L F-{L\over2}mg\\\end{cases} $$$$ \begin{aligned}x&={L\over4}\end{aligned} $$

$$ \begin{cases} m&=1.05\ut{kg}\\ r&=4.2\ut{cm}\\ L&=6.0\ut{cm}\\g&=9.80665\ut{m/s^2} \end{cases} $$ $$\theta=\tan^{-1}{r\over L}$$ $$ \begin{cases} \Sigma F_{x}&=0\\ \Sigma F_{y}&=0\\ \end{cases} $$ $$ \begin{cases} 0&=N-T\sin\theta\\ 0&=T\cos\theta-mg\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} T &={mg\over \cos\theta}\\ &={mg\over {L\over \sqrt{L^2+r^2}}}\\ &=\frac{21 \sqrt{149} g}{200}\\ ..

$$ \begin{cases} m&=13\ut{kg}\\ \theta&=55\degree\\ \phi&=25\degree\\g&=9.80665\ut{m/s^2} \end{cases} $$ $$ \begin{cases} \Sigma F_{x}&=0\\ \Sigma F_{y}&=0\\ \end{cases} $$ $$ \begin{cases} 0&=T\cos\phi-mg\sin\theta\\ 0&=-T\sin\phi-mg\cos\theta+N\\ \end{cases} $$ $$ \begin{aligned} T&={\sin\theta\over\cos\phi}mg \\ &\approx 1.1522662348306987\times10^2\ut{N}\\ &\approx 1.2\times10^2\ut{N}\\ \end..