11-32 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \vec F&=2.0\i-6.0\k\ut{N}\\ \vec r&=0.50\j-2.0\k\ut{m}\\ \vec P&=2.0\i-3.0k\ut{m}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \tau_a&=\vec r\times \vec F\\ &=-3.0\i-4.0\j-1.0\k\ut{N\cdot m} \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \tau_b&=(\vec r-\vec P)\times \vec F\\ &=-3.0\i-1.0\times10\j-1.0\k\ut{N\cdot m} \end{aligned} $$