11판/10. 회전

10-47 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 5. 11. 04:55
$$ \begin{cases} R_A&=15\ut{cm}\\ \omega_A&=10\ut{rad/s}\\ R_B&=10\ut{cm}\\ R_{B'}&=5\ut{cm}\\ R_C&=25\ut{cm}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} v_1&=R_A\cdot\omega_A\\ &=150\ut{cm/s}\\ &=1.5\ut{m/s}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \omega_B&=\frac{v_1}{R_B}\\ &=15\ut{rad/s}\\ \end{aligned} $$ $$\ab{c}$$ $$ \begin{aligned} \omega_{B'}&=\omega_B\\ &=15\ut{rad/s}\\ \end{aligned} $$ $$\ab{d}$$ $$ \begin{aligned} v_2&=R_{B'}\cdot\omega_{B'}\\ &=75\ut{cm/s}\\ &=0.75\ut{m/s}\\ &\approx 0.7\ut{m/s}\\ \end{aligned} $$ $$\ab{e}$$ $$ \begin{aligned} \omega_C&=\frac{v_2}{R_C}\\ &=3\ut{rad/s}\\ \end{aligned} $$