10-46 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \omega &= 33\frac{1}{3}\ut{rev/min}\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \omega &= \(33+\frac{1}{3}\)\ut{rev/min}\cdot\frac{1\ut{min}}{60\ut{s}}\cdot\frac{2\pi\ut{rad}}{1\ut{rev}}\\ &=\frac{10\pi}{9}\ut{rad/s}\\ &\approx 3.490658503988659\ut{rad/s}\\ &\approx 3.5\ut{rad/s}\\ \end{aligned} $$ $$\ab{b,c}$$ $$ \begin{aligned} v(r)&=r\omega\\ &=\frac{10\pi}{9}r\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} v(15\ut{cm})&=\frac{50\pi}{3}\ut{cm/s}\\ &\approx 52.35987755982989\ut{cm/s}\\ &\approx 52\ut{cm/s}\\ \end{aligned} $$ $$\ab{c}$$ $$ \begin{aligned} v(7.4\ut{cm})&=\frac{74\pi}{9}\ut{cm/s}\\ &\approx 25.830872929516076\ut{cm/s}\\ &\approx 26\ut{cm/s}\\ \end{aligned} $$