10-33 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \alpha(t\ut{s})&=6.0t^4-5.0t^2\ut{rad/s^2}\\ \omega_0&=+3.0\ut{rad/s}\\ \theta_0&=+7.0\ut{rad} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \omega(t\ut{s})&=\omega_0+\Delta \omega\\ &=\omega_0+\int_0^t\alpha\dd t\\ &=\frac{6 }{5}t^5-\frac{5 }{3}t^3+3\ut{rad/s}\\ \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \theta(t\ut{s})&=\theta_0+\Delta \theta\\ &=\theta_0+\int_0^t\omega\dd t\\ &=\frac{1}{5}t^6-\frac{5}{12} t^4+3 t+7\ut{rad}\\ \end{aligned} $$