11판/9. 질량중심과 선운동량

9-31 할리데이 11판 솔루션 일반물리학

짱세디럭스 2024. 4. 21. 16:24
{m=0.15[kg]vi=5.00i^+6.50j^+4.00k^[m/s]vf=2.00i^+3.50j^3.20k^[m/s] \begin{cases} m&=0.15\ut{kg}\\ v_i&=5.00\i+6.50\j+4.00\k\ut{m/s}\\ v_f&=2.00\i+3.50\j-3.20\k\ut{m/s}\\ \end{cases} (a)\ab{a} Δp=Δ(mv)=mΔv=920i^920j^2725k^[kgm/s]=0.45i^0.45j^1.08k^[kgm/s]0.45i^0.45j^1.1k^[kgm/s] \begin{aligned} \Delta \vec p&=\Delta (m\vec v)\\ &=m\Delta \vec v\\ &=-\frac{9}{20}\i-\frac{9}{20}\j-\frac{27}{25}\k\ut{kg\cdot m/s}\\ &=-0.45\i-0.45\j-1.08\k\ut{kg\cdot m/s}\\ &\approx -0.45\i-0.45\j-1.1\k\ut{kg\cdot m/s}\\ \end{aligned} (b)\ab{b} JA=Δp=0.45i^0.45j^1.08k^[Ns]0.45i^0.45j^1.1k^[Ns] \begin{aligned} \vec J_A&=\Delta \vec p\\ &=-0.45\i-0.45\j-1.08\k\ut{N\cdot s}\\ &\approx -0.45\i-0.45\j-1.1\k\ut{N\cdot s}\\ \end{aligned} (c)\ab{c} JB=JA=0.45i^0.45j^1.08k^[Ns]0.45i^0.45j^1.1k^[Ns] \begin{aligned} \vec J_B&=\vec J_A\\ &=-0.45\i-0.45\j-1.08\k\ut{N\cdot s}\\ &\approx -0.45\i-0.45\j-1.1\k\ut{N\cdot s}\\ \end{aligned}