6-28 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} R&=32.0\ut{m}\\ v&=6.50\ut{m/s}\\ m&=85.0\ut{kg} \end{cases} $$ $$\ab{a,b}$$ $$ \begin{aligned} \Sigma F_R&=f=\frac{mv^2}{R}\\ &=\frac{14365}{128}\ut{N}\\ &=112.2265625\ut{N}\\ &\approx 1.12\times10^2\ut{N}\\ \end{aligned} $$