5-19 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \theta_1 &= 0\\ \theta_2 &= 52\degree\\ \end{cases} $$ $$\ab{a}$$ $$ v=v_0+at, $$ $$ \begin{cases} v_1&=(0)+\(\frac{F_1}{m}\)t\\ v_2&=(0)+\(\frac{F_2}{m}\)t\\ \end{cases} $$ $$ \begin{aligned} \frac{v_1}{v_2}&=\frac{F_1}{F_2}\\ &=\frac{F\cos\theta_1}{F\cos\theta_2}\\ &=\frac{\cos0\degree}{\cos52\degree}\\ &\approx 1.624269245482744\\ &\approx 1.6\\ \end{aligned} $$ $$\ab{b}$$ $$ 2aS=v^2-{v_0}^2, $$ $$ \begin{cases} 2\frac{F_1}{m}d={v_1}^2-{0}^2\\ 2\frac{F_2}{m}d={v_2}^2-{0}^2\\ \end{cases} $$ $$ \begin{aligned} \(\frac{v_1}{v_2}\)^2&=\frac{F_1}{F_2}\\ \frac{v_1}{v_2}&=\sqrt{\frac{F\cos\theta_1}{F\cos\theta_2}}\\ &=\sqrt{\frac{\cos0\degree}{\cos52\degree}}\\ &\approx 1.274468220664111\\ &\approx 1.3\\ \end{aligned} $$