5-21 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} g_M&=1.6\ut{m/s^2}\\ a&=3.5\ut{m/s^2}\\ mg_E&=800\ut{N}\\ g_E&=9.80665\ut{m/s^2} \end{cases} $$ $$\Sigma \vec F = m\vec a,$$ $$ \begin{aligned} F-mg_M &= m a\\ F&= m(g_M+a)\\ &= \(\frac{800}{g_E}\)(g_M+a)\\ &\approx 416.0442148949948\ut{N}\\ &\approx 4.2\times10^2\ut{N}\\ \end{aligned} $$