1-4 할리데이 10판 솔루션 일반물리학

$$\begin{cases} 12 \ut{Point}=1 \ut{pica}\\ 6 \ut{pica}=1 \ut{inch}\\ 1 \ut{inch} = 2.540\ut{cm}\\ \end{cases}$$
(a) $$\begin{aligned} 0.70\ut{cm} =& 0.70\ut{cm} \times \(\frac{1 \ut{inch}}{2.540\ut{cm}}\)\times \(\frac{6 \ut{pica}}{1 \ut{inch}}\)\\ =&\frac{210}{127}\ut{pica}\\ \approx&1.65354330709\ut{pica}\\ \approx&1.65\ut{pica} \end{aligned}$$
(b) $$\begin{aligned} 0.70\ut{cm} =& 0.70\ut{cm} \times \(\frac{1 \ut{inch}}{2.540\ut{cm}}\)\times \(\frac{6 \ut{pica}}{1 \ut{inch}}\)\times \(\frac{12 \ut{Point}}{1 \ut{pica}}\)\\ =&\frac{2520}{127}\ut{Point}\\ \approx&19.842519685\ut{Point}\\ \approx&19.8\ut{Point} \end{aligned}$$