10판/1. 측정

1-2 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 7. 20. 15:07

0.75[gry2]=0.75[gry2](1[line]10[gry])2(1[inch]12[line])2(72[Point]1[inch])2=0.75121272210212212[Point2]=27100[Point2]=0.27[Point2] \begin{aligned} & 0.75\ut{gry^2} \\ =& 0.75\ut{gry^2} \(\frac{1\ut{line}}{10\ut{gry}}\)^2 \(\frac{1\ut{inch}}{12\ut{line}}\)^2 \(\frac{72\ut{Point}}{1\ut{inch}}\)^2 \\ =& \frac{0.75\cdot 1^2\cdot 1^2\cdot 72^2}{10^2\cdot12^2\cdot 1^2}\ut{Point^2} \\ =& \frac{27}{100}\ut{Point^2} \\ =& 0.27\ut{Point^2} \end{aligned}