10판/1. 측정

1-3 할리데이 10판 솔루션 일반물리학

짱세디럭스 2019. 7. 20. 15:08

$$ \begin{aligned} & 1.0\ut{mi/h} \\ =& \frac{1\ut{mi}}{1\ut{h}} \cdot \frac{1609\ut{m}}{1\ut{mi}}\cdot \frac{1\ut{h}}{3600\ut{s}} \\ =& \frac{1\cdot1609\cdot1}{1\cdot1\cdot3600}\ut{m/s} \\ \approx& 0.4469444444444444 \ut{m/s} \\ \approx& 0.45 \ut{m/s} \end{aligned} $$