3-37 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} \vec a &= 8\i\\ \vec b &= 6\j\\ \vec c &= -8\i-6\j\\ \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} \vec a\cdot\vec b&=8\cdot0+0\cdot6\\ &=0 \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \vec a\cdot\vec c&=8\cdot(-8)+0\cdot(-6)\\ &=-64 \end{aligned} $$ $$\ab{c}$$ $$ \begin{aligned} \vec b\cdot\vec c&=0\cdot(-8)+6\cdot(-6)\\ &=-36 \end{aligned} $$