2-41 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} a&=8.0t\ut{m/s^2}\\ v(2.0)&=17\ut{m/s} \end{cases} $$ $$ \begin{aligned} v&=\int a\dd t\\ &=\int 8t\dd t\\ &=4t^2+C\\ \end{aligned} $$ $$v(2)=4(2)^2+C=17,\\ C=1 $$ $$\therefore v(t)=4t^2+1$$ $$ \begin{aligned} v(5)&= 4(5)^2+1\\ &=101\ut{m/s}\\ &\approx 1.0\times10^2\ut{m/s} \end{aligned} $$