1-28 할리데이 11판 솔루션 일반물리학

$$\begin{cases} 1\ut{mol}&=6.02\times10^{23}\\ 1\ut{u}&=1\ut{g/mol}\\ \end{cases}$$ $$\begin{aligned} \Ans&={M\over N}\\ &={68\ut{g}\over 6.8\ut{mol}}\\ &=10\ut{g/mol}\\ &=10\ut{u} \end{aligned}$$