1-29 할리데이 11판 솔루션 일반물리학

$$ \begin{cases} V&=40\ut{cm}\times40\ut{cm}\times26\ut{cm} \end{cases} $$ $$\ab{a}$$ $$ \begin{aligned} V&=41600\ut{cm^3}\\ &=41.6\ut{L}\\ &=41.6\ut{L}\cdot\frac{16\ut{bottle}}{11.356\ut{L}}\\ &=\frac{166400}{2839}\ut{bottle} \approx58.61218738992603\ut{bottle}\\ &=\(2\cdot20+16+2+\frac{1738}{2839}\)\ut{bottle}\\ &=2\ut{nebuchadnezzar}+1\ut{balthazar}+1\ut{magnum}+\frac{1738}{2839}\ut{bottle} \end{aligned} $$ $$\ab{b}$$ $$ \begin{aligned} \Ans&=\frac{1738}{2839}\ut{bottle}\\ &\approx0.6121873899260303\ut{bottle}\\ &\approx0.61\ut{bottle}\\ \end{aligned} $$ $$\ab{c}$$ $$ \begin{aligned} \Ans&=\frac{1738}{2839}\ut{bottle}\\ &=\frac{1738}{2839}\ut{bottle}\cdot\frac{11.356\ut{L}}{16\ut{bottle}}\\ &=\frac{869}{2000}\ut{L}\\ &=0.4345\ut{L}\\ &\approx0.43\ut{L} \end{aligned} $$