11판/1. 측정

1-25 할리데이 11판 솔루션 일반물리학

짱세디럭스 2022. 10. 4. 21:16
$$ \begin{cases} 1\ut{cord}&=8\ut{ft}\times4\ut{ft}\times4\ut{ft}\\ &=128\ut{ft^3} \end{cases} $$ $$ \begin{aligned} \Ans&=2\ut{cord}\\ &=2\ut{cord}\cdot\frac{128\ut{ft^3}}{1\ut{cord}}\cdot\(\frac{12\ut{in}}{1\ut{ft}}\cdot\frac{2.54\ut{cm}}{1\ut{in}}\cdot\frac{1\ut{m}}{100\ut{cm}}\)^3\\ &=\frac{1769802912}{244140625}\ut{m^3}\\ &\approx7.249112727552\ut{m^3}\\ &\approx7.25\ut{m^3}\\ \end{aligned} $$