11판/1. 측정

1-2 할리데이 11판 솔루션 일반물리학

짱세디럭스 2022. 9. 22. 21:42

{Δx1=23[cm]Δy1=19[cm]Δx2=28[cm]ΣΔy=9.50[m] \begin{cases} \Delta x_1 &= 23\ut{cm}\\ \Delta y_1 &= 19\ut{cm}\\ \Delta x_2 &= 28\ut{cm}\\ \Sigma \Delta y &= 9.50\ut{m}\\ \end{cases} ΣΔx2ΣΔx1=? \Sigma \Delta x_2 - \Sigma \Delta x_1=? N=ΣΔyΔy1=9.50[m]19[cm]=50 \begin{aligned} N &= \frac{\Sigma \Delta y}{\Delta y_1} \\ &= \frac{9.50\ut{m}}{19\ut{cm}}\\ &= 50 \end{aligned} Ans=ΣΔx2ΣΔx1=NΔx2NΔx1=N(Δx2Δx1)=50(28[cm]23[cm])=250[cm]=2.5[m] \begin{aligned} \Ans&=\Sigma \Delta x_2 - \Sigma \Delta x_1\\ &= N \cdot \Delta x_2 - N \cdot \Delta x_1\\ &= N \(\Delta x_2 - \Delta x_1 \)\\ &= 50 \cdot (28\ut{cm}-23\ut{cm})\\ &= 250 \ut{cm} \\ &= 2.5\ut{m} \end{aligned}