11판/1. 측정

1-4 할리데이 11판 솔루션 일반물리학

짱세디럭스 2022. 9. 24. 14:55
{1[tuffet]=2[pecks]=0.50[Imperial bushel]1[Imperial bushel]=36.3687[L] \begin{cases} 1 \ut{tuffet} &= 2\ut{pecks}\\ &=0.50\ut{Imperial~bushel}\\ 1\ut{Imperial~bushel}&=36.3687\ut{L} \end{cases} 5.60[tuffet]=? 5.60\ut{tuffet}=? (a)\ab{a} in[peck]? \text{in} \ut{peck} ? 5.60[tuffet]=5.60[tuffet]×2[pecks]1[tuffet]=11.2[pecks] \begin{aligned} 5.60\ut{tuffet}&=5.60\ut{tuffet}\times\frac{2\ut{pecks}}{1 \ut{tuffet}}\\ &=11.2\ut{pecks} \end{aligned} (b)\ab{b} in[Imperial bushel]? \text{in} \ut{Imperial~bushel} ? 5.60[tuffet]=5.60[tuffet]×0.50[Imperial bushel]1[tuffet]=2.8[Imperial bushel] \begin{aligned} 5.60\ut{tuffet}&=5.60\ut{tuffet}\times\frac{0.50\ut{Imperial~bushel}}{1 \ut{tuffet}}\\ &=2.8\ut{Imperial~bushel} \end{aligned} (c)\ab{c} in[L]? \text{in} \ut{L} ? 5.60[tuffet]=5.60[tuffet]×0.50[Imperial bushel]1[tuffet]×36.3687[L]1[Imperial bushel]=101.83236[L]102[L] \begin{aligned} 5.60\ut{tuffet}&=5.60\ut{tuffet}\times\frac{0.50\ut{Imperial~bushel}}{1 \ut{tuffet}}\times\frac{36.3687\ut{L}}{1\ut{Imperial~bushel}}\\ &=101.83236\ut{L}\\ &\approx{102\ut{L}} \end{aligned}